*is one of the basic concepts in the field of modern electronic computing. In electronic analog computation any equation can be solved by using some analog circuits which is designed by using op-amps .In my assignment I try to present the concept of electronic analog computation by solving a differential equation with a correspondent circuit .*

**analog computation**
Electronic analog computation is such kind of electronic computation in which basic analog computing elements such as adders ,

In this a differential equation is solved by electronic analog computation.*,multipliers,***integrators***etc are used to solve any desired equation such as differential equations etc .It is the basic concepts of analog computer.***comparators**
Let a differential equation be :

^{ }

^{ }D

^{2}v+k

_{1}Dv+k

_{2}v-v

_{1}=0……………….(1) Where, k

_{1}and k

_{2}are constant terms.

In the starting I assumed that D

^{2}v is available in the form of a voltage .Then by means of an*I will get the voltage proportional to Dv. A second integrator gives the voltage proportional to v .Then an adder gives –( k***integrator**_{1}Dv+k_{2}v-v_{1}) From the equation it is equal to D^{2}v
and hence the output of this summing

*is fed to the input terminal ,where I had assumed that D***amplifier**^{2}v was available in the first place.
The integrator 1 has a

**time constant***RC*=1s, and hence its output at terminal 1 is –Dv .This voltage is fed to a similar integrator 2 and the voltage at terminal 2 is +v. The voltage at terminal 1 is fed to summing amplifier 1 which gain is 1 and in the output terminal 3 I get + k_{1}Dv- v_{1.}
where k

_{1}=(R/R_{1}).At the end the output of terminal 2 and 3 are fed to summing amplifier 2,from where I will get^{ }D^{2}v= - (k_{1}Dv+k_{2}v-v_{1}) at terminal 4.
Fig1.1: Electronic analog computing circuit for calculating a differential equation .

*.But we have to careful to set the gain of the circuits because in some steps the constant term of the equation is represent by the*

**op-amp***of the correspondent circuit .So, we have to design the circuits according to gain which represents the constant term*

**gain**
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